A projectile is launched from ground level at an angle of 30.0° above horizontal with a speed of 10.0 m/s. If the projectile is moving over level ground, what is the maximum height above the ground that the projectile reaches?
A)2.54 m
B)1.27 m
C)5.00 m
D)3.54 m
E)20.0 m

Question

Quizplus · Accepted Answer

The vertical component of the initial velocity is $v_{0y} = 10.0 \sin(30°) = 5.0 \, \text{m/s}$. Using the formula for maximum height $h = \frac{v_{0y}^2}{2g}$, where $g = 9.8 \, \text{m/s}^2$, we get $h = \frac{5.0^2}{2 \times 9.8} = 1.27 \, \text{m}$.

A Projectile Is Launched from Ground Level at an Angle