Solve.
-$$x ^ { 2 } - 4 x - 12

Name: Solve. -\[x ^ { 2 } - 4 x - 12 < 0\] A) $( - 2,6 )$ B) $( 6 , \infty )$ C) $( - \infty , - 2 ) \cup ( 6 , \infty )$ D) $( - \infty , - 2 )$
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Question

Solve.
-$$x ^ { 2 } - 4 x - 12 < 0$$
A) $( - 2,6 )$
B) $( 6 , \infty )$
C) $( - \infty , - 2 ) \cup ( 6 , \infty )$
D) $( - \infty , - 2 )$

Quizplus · Accepted Answer

To solve the inequality $x^2 - 4x - 12 < 0$, first factor the quadratic equation. It factors to $(x - 6)(x + 2) < 0$. The roots are $x = 6$ and $x = -2$. The inequality is satisfied between the roots, so the solution is $x \in (-2, 6)$.

Solve - x2−4x−12<0x ^ { 2 } - 4 x - 12 < 0x2−4x−12<0

Solve
- $x ^ { 2 } - 4 x - 12 < 0$