Solve. $\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1$
A) $- 3 , - 1$
B) $3 , - 1$
C) 3
D) No solution
-Solve. $\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1$
A) $- 3 , - 1$
B) $3 , - 1$
C) 3
D) No solution

Question

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The Answer of Solve. $\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1$
A) $- 3 , - 1$
B) $3 , - 1$
C) 3
D) No solution
-Solve. $\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1$
A) $- 3 , - 1$
B) $3 , - 1$
C) 3
D) No solution

Solve 2x+3−x+1=1\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 12x+3​−x+1​=1

Solve $\sqrt { 2 x + 3 } - \sqrt { x + 1 } = 1$