Solve.
-$$9 x ^ { 2 } - 18 x - 16 = 0$$
A) $\frac { 8 } { 9 } , - \frac { 2 } { 9 }$
B) $- \frac { 8 } { 3 } , \frac { 2 } { 3 }$
C) $- \frac { 2 } { 9 } , - \frac { 14 } { 9 }$
D) $\frac { 8 } { 3 } , - \frac { 2 } { 3 }$

Question

Quizplus · Accepted Answer

This quadratic equation can be solved using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 9$, $b = -18$, and $c = -16$. Substituting these values gives the solutions $x = \frac{8}{3}$ and $x = -\frac{2}{3}$.

Solve - 9x2−18x−16=09 x ^ { 2 } - 18 x - 16 = 09x2−18x−16=0

Solve
- $9 x ^ { 2 } - 18 x - 16 = 0$