Provide an appropriate response.
-To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of $25.2$ milligrams and standard deviation of $2.7$ milligrams for a sample of $\mathrm { n } = 9$ cigarettes. The FDA claims that the mean nicotine content exceeds $28.3$ milligrams for this brand of cigarette, and their stated reliability is $95 \%$. Do you agree?
A) No, since the value $28.3$ does not fall in the $95 \%$ confidence interval.
B) Yes, since the value $28.3$ does fall in the $95 \%$ confidence interval.
C) Yes, since the value $28.3$ does not fall in the $95 \%$ confidence interval.
D) No, since the value $28.3$ does fall in the $95 \%$ confidence interval.

Question

Quizplus · Accepted Answer

The $95\%$ confidence interval for the mean nicotine content can be calculated using the sample mean, standard deviation, and sample size. Given the sample mean ($25.2$ mg), standard deviation ($2.7$ mg), and sample size ($n=9$), the confidence interval does not include the value $28.3$ mg, indicating that the FDA's claim that the mean exceeds $28.3$ mg is not supported by the sample data.

Provide an Appropriate Response 25.225.225.2 Milligrams and Standard Deviation Of 2.72.72.7 Milligrams for a Sample Of

Provide an Appropriate Response $25.2$ Milligrams and Standard Deviation Of $2.7$ Milligrams for a Sample Of