Identify Discrete Probability Distributions
-Given the table of probabilities for the random variable $x$, does this form a probability distribution? Answer Yes or No.
$\begin{array}{|c|c|c|c|c|c|}
\hline x & 0 & 1 & 2 & 3 & 4 \
\hline P(x) & 0.02 & 0.07 & 0.22 & 0.27 & 0.42 \
\hline
\end{array}$

A) Yes
B) $\mathrm { No }$

Question

Identify Discrete Probability Distributions
-Given the table of probabilities for the random variable $x$, does this form a probability distribution? Answer Yes or No.
$\begin{array}{|c|c|c|c|c|c|}
\hline x & 0 & 1 & 2 & 3 & 4 \
\hline P(x) & 0.02 & 0.07 & 0.22 & 0.27 & 0.42 \
\hline
\end{array}$

A) Yes
B) $\mathrm { No }$

Quizplus · Accepted Answer

The probabilities sum up to 1 (0.02 + 0.07 + 0.22 + 0.27 + 0.42 = 1.00), which is a requirement for a set of probabilities to form a probability distribution.

Identify Discrete Probability Distributions -Given the Table of Probabilities for the Random

Identify Discrete Probability Distributions
-Given the Table of Probabilities for the Random