Determine Whether a Probability Experiment is a Hypergeometric Experiment
-A university must choose a team of 5 students to participate in a TV quiz show. The students will be chosen at random from a pool of 36 potential participants of whom 29 are women. The random variable $\mathrm { X }$ represents the number of women on the team.
A) hypergeometric; $\mathrm { N } = 36 , \mathrm { n } = 5 , \mathrm { k } = 29 , \mathrm { x } = 0,1,2,3,4,5$
B) hypergeometric; $\mathrm { N } = 36 , \mathrm { n } = 29 , \mathrm { k } = 5 , \mathrm { x } = 0,1,2,3,4,5$
C) hypergeometric; $\mathrm { N } = 36 , \mathrm { n } = 5 , \mathrm { k } = 29 , \mathrm { x } = 0,1,2 , \ldots , 29$
D) not hypergeometric

Question

Quizplus · Accepted Answer

This is a hypergeometric experiment because it involves selecting without replacement from a finite population where each selection is not independent. The parameters correctly match the definition: $N = 36$ (total number of potential participants), $n = 5$ (number of draws), $k = 29$ (number of successes in the population), and $x$ can take on any value from 0 to 5 (possible number of women selected).

Determine Whether a Probability Experiment Is a Hypergeometric Experiment -A X\mathrm { X }X

Determine Whether a Probability Experiment Is a Hypergeometric Experiment
-A $\mathrm { X }$