Determine and Interpret z-Scores
-Many firms use on-the-job training to teach their employees new software. Suppose you work in the personnel department of a firm that just finished training a group of its employees in new software, and you have been requested to review the performance of one of the trainees on the final test that was given to all trainees. The mean and standard deviation of the test scores are 79 and 4, respectively, and the distribution of scores is mound-shaped and symmetric. Suppose the trainee in question received a score of 74. Compute the trainee s z-score.
A) $z = - 1.25$
B) $z = 1.25$
C) $\mathrm { z } = - 0.89$
D) $z = 0.89$

Question

Determine and Interpret z-Scores
-Many firms use on-the-job training to teach their employees new software. Suppose you work in the personnel department of a firm that just finished training a group of its employees in new software, and you have been requested to review the performance of one of the trainees on the final test that was given to all trainees. The mean and standard deviation of the test scores are 79 and 4, respectively, and the distribution of scores is mound-shaped and symmetric. Suppose the trainee in question received a score of 74. Compute the trainee s z-score. 
A) $z = - 1.25$
B) $z = 1.25$
C) $\mathrm { z } = - 0.89$
D) $z = 0.89$

Quizplus · Accepted Answer

The z-score is calculated using the formula $z = \frac{(X - \mu)}{\sigma}$, where $X$ is the score in question, $\mu$ is the mean, and $\sigma$ is the standard deviation. Substituting the given values, $z = \frac{(74 - 79)}{4} = -1.25$.

Determine and Interpret Z-Scores -Many Firms Use On-The-Job Training to Teach

Determine and Interpret Z-Scores
-Many Firms Use On-The-Job Training to Teach