Solved

Provide an Appropriate Response α=0.05\alpha = 0.05 Level of Significance to Support the Hypothesis That Cassie's Walk

Question 10

Multiple Choice

Provide an appropriate response.
-Wanting to enjoy the beautiful weather, Cassie took a walk with no destination in mind. At each four-way intersection, she randomly decided to head either north or east. A summary of her walk is shown below.
 Provide an appropriate response. -Wanting to enjoy the beautiful weather, Cassie took a walk with no destination in mind. At each four-way intersection, she randomly decided to head either north or east. A summary of her walk is shown below.    Is there evidence at the  \alpha = 0.05  level of significance to support the hypothesis that Cassie's walk was not random? A)   z = - 0.26  Since  | \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject  \mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random. B)   z = - 0.91  Since  | \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject  \mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random. C)   z = - 5.43  Since  | \mathrm { z } | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject  \mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random. D)   z = - 3.50  Since  | z | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject  \mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.

Is there evidence at the α=0.05\alpha = 0.05 level of significance to support the hypothesis that Cassie's walk was not random?


A) z=0.26z = - 0.26
Since z<z0.025=1.96| \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject H0\mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random.
B) z=0.91z = - 0.91
Since z<z0.025=1.96| \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject H0\mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random.
C) z=5.43z = - 5.43
Since z>z0.025=1.96| \mathrm { z } | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject H0\mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.
D) z=3.50z = - 3.50
Since z>z0.025=1.96| z | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject H0\mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents