Use the following information to answer questions (16)-(18). From a random sample of workers at a large
corporation you find that 58% of 200 went on a vacation last year away from home for at least a week.
-What is the margin of error for the 95% confidence interval of (0.50, 0.66) of coworkers who went on a vacation last year away from home for at least a week?
A)0.08
B)0.16
C)0.58
D)0.04

Question

Quizplus · Accepted Answer

The margin of error is calculated as half the width of the confidence interval. The interval is from 0.50 to 0.66, so the width is 0.66 - 0.50 = 0.16. Half of that is 0.08, which is the margin of error.

Use the Following Information to Answer Questions (16)-(18)