Find $P _ { k + 1 }$ for the given $P _ { k }$.
$$P _ { k } = \frac { 4 } { k ( k + 1 ) }$$
A) $P _ { k + 1 } = \frac { 4 } { k ( k + 1 ) } + 1$
B) $P _ { k + 1 } = \frac { 4 } { k ( k + 1 ) } + \frac { 4 } { ( k + 1 ) ( k + 2 ) }$
C) $P _ { k + 1 } = \frac { 4 } { ( k + 1 ) ( k + 2 ) }$
D) $P _ { k + 1 } = \frac { 4 } { k ( k + 2 ) }$
E) $\quad P _ { k + 1 } = \frac { 16 } { ( k + 1 ) ( k + 2 ) }$

Question

Quizplus · Accepted Answer

To find $P_{k+1}$, replace $k$ with $k+1$ in the given formula: $P_{k+1} = \frac{4}{(k+1)((k+1)+1)} = \frac{4}{(k+1)(k+2)}$.

Find Pk+1P _ { k + 1 }Pk+1​ For the Given PkP _ { k }Pk​

Find $P _ { k + 1 }$ For the Given $P _ { k }$