The mean number of errors per page made by a member of the word processing pool for a large company is thought to be 1.5 with the number of errors distributed according to a Poisson distribution. If three pages are examined, what is the probability that more than 3 errors will be observed?
A) 0.6577
B) 0.6969
C) 0.7324
D) 0.7860

Question

Quizplus · Accepted Answer

The probability of observing more than 3 errors in three pages is given by the Poisson distribution as:P(X > 3) = 1 - P(X <= 3) = 1 - (e^(-1.5) * (1.5^0 + 1.5^1 + 1.5^2 + 1.5^3)) / 4!) = 0.6577

The Mean Number of Errors Per Page Made by a Member