The bottlers of a new fruit juice daily select a random sample of 12 bottles of the drink to estimate the mean quantity of juice in the bottles filled that day. On one such day, the following results were observed: = 12.03; s = 0.12. Based on this information, the margin of error associated with a 90 percent confidence interval estimate for the population mean is 1.7959 ounces.

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Quizplus · Accepted Answer

The margin of error for a confidence interval is calculated using the formula $ME = t_{\alpha/2} \times \frac{s}{\sqrt{n}}$, where $t_{\alpha/2}$ is the t-score corresponding to the desired confidence level, $s$ is the sample standard deviation, and $n$ is the sample size. The given values do not provide enough information to directly confirm the margin of error as 1.7959 ounces without knowing the t-score for the 90% confidence level and performing the calculation.

The Bottlers of a New Fruit Juice Daily Select a Random