A grocery store manager is interested in estimating the mean weight of apples received in a shipment. If she wishes to have the estimate be within ±.05 pound with 90 percent confidence, the sample size should be 103 apples if she believes that the standard deviation is .08 pound.

Question

Quizplus · Accepted Answer

The sample size required for estimating the mean weight of apples with a specific margin of error and confidence level is calculated using the formula for the sample size of a mean, which is $n = \left(\frac{Z \cdot \sigma}{E}\right)^2$, where $Z$ is the Z-score corresponding to the desired confidence level, $\sigma$ is the estimated standard deviation, and $E$ is the desired margin of error. Without calculating the exact number, the statement provides a specific sample size (103 apples) without showing the calculation or considering the Z-score for a 90% confidence level, which makes it impossible to verify the correctness of the statement without additional information or calculation.

A Grocery Store Manager Is Interested in Estimating the Mean