A hospital emergency room has collected a sample of n = 40 to estimate the mean number of visits per day. It has found the standard deviation is 32. Using a 90 percent confidence level, what is its margin of error?
A) Approximately ±1.5 visits
B) About ±9.9 visits
C) Approximately ±8.3 visits
D) About ±1.3 visits

Question

Quizplus · Accepted Answer

The margin of error is calculated using the formula: E = Z * (σ/√n). For a 90% confidence level, the Z-score is approximately 1.645. Plugging in the values: E = 1.645 * (32/√40) ≈ 8.3 visits.

A Hospital Emergency Room Has Collected a Sample of N