The model $\sqrt { \text { distance } } = 3.30 + 0.235$ (speed. can be used to predict the stopping distance (in feet. for a car traveling at a specific speed (in mph.) According to this model, about how much distance will a car going $65 \mathrm { mph }$ need to stop?
A) $729.0$ feet
B) $345.0$ feet
C) $27.0$ feet
D) $4.3$ feet
E) $18.6$ feet

Question

Quizplus · Accepted Answer

To find the stopping distance for a car going 65 mph, substitute the speed into the model: $\sqrt{\text{distance}} = 3.30 + 0.235 \times 65$. Solving this gives $\sqrt{\text{distance}} \approx 18.575$. Squaring both sides to solve for distance gives $\text{distance} \approx 729.0$ feet.

The Model distance =3.30+0.235\sqrt { \text { distance } } = 3.30 + 0.235 distance ​=3.30+0.235

The Model $\sqrt { \text { distance } } = 3.30 + 0.235$