Solve the problem.
-Let $\mathrm { A } = \left[ \begin{array} { r r r } 6 & - 1 & - 2 \ - 4 & 7 & - 2 \end{array} \right]$ and $\mathrm { B } = \left[ \begin{array} { r r r } 7 & 6 & 2 \ - 7 & 7 & - 9 \ - 4 & - 9 & 7 \end{array} \right]$. Find $\mathrm { AB }$.
A) $\left[ \begin{array} { r r r } 6 & - 1 & - 2 \ - 4 & 7 & - 2 \ 7 & 7 & - 2 \ - 7 & 7 & - 9 \ - 4 & - 4 & 7 \end{array} \right]$
B) $\left[ \begin{array} { r r r } 57 & 47 & 7 \ - 69 & 43 & - 85 \end{array} \right]$
C) $\left[ \begin{array} { r r r } 42 & - 6 & - 4 \ 28 & 49 & 18 \ 16 & - 63 & - 14 \end{array} \right]$
D) $\left[ \begin{array} { r r } 57 & - 69 \ 47 & 43 \ 7 & - 85 \end{array} \right]$

Question

Quizplus · Accepted Answer

To find the product $AB$, multiply each row of matrix $A$ by each column of matrix $B$ and sum the products. The result is a 2x3 matrix, matching option B.

Solve the Problem A=[6−1−2−47−2]\mathrm { A } = \left[ \begin{array} { r r r } 6 & - 1 & - 2 \\ - 4 & 7 & - 2 \end{array} \right]A=[6−4​−17​−2−2​]

Solve the Problem $\mathrm { A } = \left[ \begin{array} { r r r } 6 & - 1 & - 2 \\ - 4 & 7 & - 2 \end{array} \right]$