Solve the problem.
-An arch in the form of a semiellipse is 52 ft wide at the base and has a height of 20 ft. How wide is the arch at a height of 12 ft above the base?
A) 41.6 ft
B) 17.7 ft
C) 35.5 ft
D) 20.8 ft

Question

Quizplus · Accepted Answer

The equation of the ellipse is (x^2/26^2) + (y^2/20^2) = 1. Substituting y = 12, we get x^2/26^2 = 1 - 12^2/20^2, so x = 41.6 ft.

Solve the Problem. -An Arch in the Form of a Semiellipse Is 52