Suppose A = {2, 3, 6, 9, 10, 12, 14, 18, 20} and R is the partial order relation deﬁned on A where xR y means x is a divisor or y .
(a) Draw the Hasse diagram for $R$.
(b) Find all maximal elements.
(c) Find all minimal elements.
(d) Find $\operatorname { lub } ( \{ 2,9 \} )$.
(e) Find $\operatorname { lub } ( \{ 3,10 \} )$.
(f) Find $\operatorname { glb } ( \{ 14,10 \} )$.

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The Answer of Suppose A = {2, 3, 6, 9, 10, 12, 14, 18, 20} and R is the partial order relation deﬁned on A where xR y means x is a divisor or y .
(a) Draw the Hasse diagram for $R$.
(b) Find all maximal elements.
(c) Find all minimal elements.
(d) Find $\operatorname { lub } ( \{ 2,9 \} )$.
(e) Find $\operatorname { lub } ( \{ 3,10 \} )$.
(f) Find $\operatorname { glb } ( \{ 14,10 \} )$.

Suppose a = {2, 3, 6, 9, 10, 12, 14 RRR

Suppose a = {2, 3, 6, 9, 10, 12, 14 $R$