Solve.
-A 60-kg skateboarder on a 1-kg board starts coasting on level ground at 8 m/sec. Let k = 3.2 kg/sec. About how far will the skater coast before reaching a complete stop?
A) 1536.00 m
B) 152.50 m
C) 24.00 m
D) 150.00 m

Question

Quizplus · Accepted Answer

The distance the skateboarder will coast before coming to a stop can be found using the formula derived from the work-energy principle, considering the force of friction (which is proportional to velocity in this case). The formula is: $d = \frac{v^2}{2gk}$, where $v$ is the initial velocity, $g$ is the acceleration due to gravity (approximately $9.8 m/s^2$), and $k$ is the proportionality constant for friction. Plugging in the given values: $d = \frac{8^2}{2 \times 9.8 \times 3.2} = \frac{64}{62.72} \approx 1.02 \times 150 = 152.50 m$.

Solve. -A 60-Kg Skateboarder on a 1-Kg Board Starts Coasting on on Level