Solve the Problem $\mathrm { V } = \mathrm { IR }$

Solve the problem. Round your answer, if appropriate.
-Electrical systems are governed by Ohm's law, which states that $\mathrm { V } = \mathrm { IR }$ , where $\mathrm { V } =$ voltage, $\mathrm { I } = \mathrm { current }$ , and $\mathrm { R } =$ resistance. If the current in an electrical system is decreasing at a rate of $4 \mathrm {~A} / \mathrm { s }$ while the voltage remains constant at $16 \mathrm {~V}$ , at what rate is the resistance increasing (in $\Omega / \mathrm { sec }$ ) when the current is 20 A? (Do not round your answer.)

A) $\frac { 4 } { 25 } \Omega / \mathrm { sec }$
B) $\frac { 64 } { 5 } \Omega / \mathrm { sec }$
C) $\frac { 16 } { 5 } \Omega / \mathrm { sec }$
D) $\frac { 5 } { 16 } \Omega / \mathrm { sec }$