Find the linearization L(x) of f(x) at x = a.
-$$f ( x ) = \frac { 1 } { 2 x - 6 } , a = 0$$
A) $L ( x ) = - \frac { 1 } { 18 } x + \frac { 1 } { 36 }$
B) $L ( x ) = \frac { 1 } { 18 } x - \frac { 1 } { 6 }$
C) $L ( x ) = \frac { 1 } { 18 } x + \frac { 1 } { 36 }$
D) $L ( x ) = - \frac { 1 } { 18 } x - \frac { 1 } { 6 }$

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The Answer of Find the linearization L(x) of f(x) at x = a.
-$$f ( x ) = \frac { 1 } { 2 x - 6 } , a = 0$$
A) $L ( x ) = - \frac { 1 } { 18 } x + \frac { 1 } { 36 }$
B) $L ( x ) = \frac { 1 } { 18 } x - \frac { 1 } { 6 }$
C) $L ( x ) = \frac { 1 } { 18 } x + \frac { 1 } { 36 }$
D) $L ( x ) = - \frac { 1 } { 18 } x - \frac { 1 } { 6 }$

Find the Linearization L(x) of F(x) at X = A f(x)=12x−6,a=0f ( x ) = \frac { 1 } { 2 x - 6 } , a = 0f(x)=2x−61​,a=0

Find the Linearization L(x) of F(x) at X = A $f ( x ) = \frac { 1 } { 2 x - 6 } , a = 0$