Solve the problem.
-$\mathrm { V } = \frac { 4 } { 3 } \pi \mathrm { r } ^ { 3 }$, where $\mathrm { r }$ is the radius, in centimeters. By approximately how much does the volume of a sphere increase when the radius is increased from $2.0 \mathrm {~cm}$ to $2.1 \mathrm {~cm}$ ? (Use $3.14$ for $\pi$.)
A) $0.3 \mathrm {~cm} ^ { 3 }$
B) $4.8 \mathrm {~cm} ^ { 3 }$
C) $5.0 \mathrm {~cm} ^ { 3 }$
D) $5.2 \mathrm {~cm} ^ { 3 }$

Question

Quizplus · Accepted Answer

The volume of a sphere is given by the formula $V = \frac{4}{3}\pi r^3$. If the radius is increased from $2.0 \mathrm{~cm}$ to $2.1 \mathrm{~cm}$, the change in volume is:$$\Delta V = V_2 - V_1 = \frac{4}{3}\pi (2.1^3 - 2.0^3) \approx 5.0 \mathrm{~cm}^3$$Therefore, the volume of the sphere increases by approximately $5.0 \mathrm{~cm}^3$.

Solve the Problem V=43πr3\mathrm { V } = \frac { 4 } { 3 } \pi \mathrm { r } ^ { 3 }V=34​πr3

Solve the Problem $\mathrm { V } = \frac { 4 } { 3 } \pi \mathrm { r } ^ { 3 }$