Find the limit.
-$$\lim _ { x \rightarrow } \frac { 5 x + 1 } { 16 x - 7 }$$
A) $- \frac { 1 } { 7 }$
B) $\frac { 5 } { 16 }$
C) 0
D) $\infty$

Question

Quizplus · Accepted Answer

To find the limit, we need to divide both the numerator and the denominator by the highest power of x. Here, the highest power of x is x. So, dividing both by x, we get:
$$\lim_{x\rightarrow}\frac{5+\frac{1}{x}}{16-\frac{7}{x}}$$
Now, as x approaches infinity, the $\frac{1}{x}$ and $\frac{7}{x}$ terms become very small compared to 5 and 16. So, we can ignore them and just evaluate the limit as:
$$\lim_{x\rightarrow}\frac{5}{16}=\frac{5}{16}$$
Therefore, the best choice is B.

Find the Limit lim⁡x→5x+116x−7\lim _ { x \rightarrow } \frac { 5 x + 1 } { 16 x - 7 }x→lim​16x−75x+1​

Find the Limit $\lim _ { x \rightarrow } \frac { 5 x + 1 } { 16 x - 7 }$