Solve the problem.
-A bullet is fired with a muzzle velocity of $1005 \mathrm { ft } / \mathrm { sec }$ from a gun aimed at an angle of $17 ^ { \circ }$ above the horizontal. Find the horizontal component of the velocity.
A) 293.8 ft/sec
B) 961.1 ft/sec
C) 307.3 ft/sec
D) -276.5 ft/sec

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be found using the formula $v_x = v \cos(\theta)$, where $v = 1005 \, \text{ft/sec}$ is the muzzle velocity and $\theta = 17^\circ$ is the angle. Thus, $v_x = 1005 \cos(17^\circ) \approx 961.1 \, \text{ft/sec}$.

Solve the Problem 1005ft/sec1005 \mathrm { ft } / \mathrm { sec }1005ft/sec

Solve the Problem $1005 \mathrm { ft } / \mathrm { sec }$