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Solve the Problem 1994.1994 . Then Estimate the Country's Population, in Millions, in 2004

Question 152

Multiple Choice

Solve the problem.
-The following table shows a country's population from 1995 to 1998:  Solve the problem. -The following table shows a country's population from 1995 to 1998:    Divide the population for each year by the population in the preceding year. Use this ratio to write the general term of the geometric sequence describing the country's population growth n years after  1994 .  Then estimate the country's population, in millions, in 2004 . A)   \mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.04 )  ^ { \mathrm { n } - 1 } ; 14.09  million B)   \mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.04 )  ^ { \mathrm { n } - 1 } ; 14.65  million C)   \mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.03 )  ^ { \mathrm { n } - 1 } ; 16.73  million D)   a _ { n } = 9.90 ( 1.03 )  ^ { n - 1 } ; 15.78  million

Divide the population for each year by the population in the preceding year. Use this ratio to write the general term of the geometric sequence describing the country's population growth n years after 1994.1994 . Then estimate the country's population, in millions, in 2004 .


A) an=9.90(1.04) n1;14.09\mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.04 ) ^ { \mathrm { n } - 1 } ; 14.09 million
B) an=9.90(1.04) n1;14.65\mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.04 ) ^ { \mathrm { n } - 1 } ; 14.65 million
C) an=9.90(1.03) n1;16.73\mathrm { a } _ { \mathrm { n } } = 9.90 ( 1.03 ) ^ { \mathrm { n } - 1 } ; 16.73 million
D) an=9.90(1.03) n1;15.78a _ { n } = 9.90 ( 1.03 ) ^ { n - 1 } ; 15.78 million

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