Solve the equation.
-$$\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }$$

Question

Quizplus · Accepted Answer

The given equation simplifies to an identity that is not valid for any real value of $x$. The denominator on the right side, $x^2 + 7x + 12$, factors to $(x+4)(x+3)$, which are the denominators of the fractions on the left side. However, when you attempt to solve the equation by finding a common denominator and simplifying, you'll find that the equation simplifies to $0 = -1$, which is a contradiction, indicating there are no solutions.

Solve the Equation 1x+4+2x+3=−1x2+7x+12\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }x+41​+x+32​=x2+7x+12−1​

Solve the Equation $\frac { 1 } { x + 4 } + \frac { 2 } { x + 3 } = \frac { - 1 } { x ^ { 2 } + 7 x + 12 }$