Given the following reaction in a voltaic cell: Cu(s) + 2Ag⁺(aq)$\rightarrow$2Ag(s) + Cu²⁺(aq) Which of the following statements is correct?

Question

Quizplus · Accepted Answer

In a voltaic cell, the anode is the electrode where oxidation occurs and the cathode is where reduction occurs. Looking at the given reaction, we can see that Cu(s) is being oxidized to CuS1U1P12+S1S1P0(aq), indicating that it is the anode. Therefore, option A is correct. Option B is incorrect because oxidation is occurring at the copper electrode, not the silver electrode. Option C is incorrect because there is clearly a reduction reaction happening in the cell (Ag1U1P1+S1S1P0(aq) F1F1F1S1F1F1F10 2Ag(s)). Option D is incorrect because Ag(s) is undergoing reduction and therefore cannot be the anode. Option E is also incorrect because the number of electrons transferred in the reaction is not specified in the given equation.

Given the Following Reaction in a Voltaic Cell: Cu(s) →\rightarrow→ 2Ag(s) + Cu2+(aq) Which of the Following Statements Is Correct

Given the Following Reaction in a Voltaic Cell: Cu(s) $\rightarrow$ 2Ag(s) + Cu²⁺(aq) Which of the Following Statements Is Correct