Given a fixed amount of gas in a rigid container (no change in volume), what pressure will the gas exert if the pressure is initially 1.50 atm at 22.0^oC, and the temperature is changed to 11.0^oC?

Question

Quizplus · Accepted Answer

According to the Ideal Gas Law, PV=nRT, the pressure (P) and temperature (T) are directly proportional when the volume (V) and amount of gas (n) are constant. Therefore, we can use the following equation to solve for the final pressure (P2):
P1/T1 = P2/T2
where P1 and T1 are the initial pressure and temperature, and T2 is the final temperature. 
Plugging in the values: 
(1.50 atm)/(295 K) = P2/(284 K)
Solving for P2: 
P2 = (1.50 atm)(284 K)/(295 K) = 1.44 atm
Therefore, the answer is D) 1.44 atm.

Given a Fixed Amount of Gas in a Rigid Container