A sample of gas initially occupies 2.50 L at a pressure of 0.900 atm at 22.0^oC.What will the pressure be if the temperature is changed to 56.5^oC, and the volume is changed to 1.50 L?

Question

Quizplus · Accepted Answer

Using the combined gas law, we can solve for the final pressure:

(P1V1/T1) = (P2V2/T2)
(0.900 atm)(2.50 L)/(295 K) = P2(1.50 L)/(329.5 K)
Solving for P2: P2 = (0.900 atm)(2.50 L)(329.5 K)/(295 K)(1.50 L) = 1.68 atm

Therefore, the pressure will be 1.68 atm at 56.5°C and a volume of 1.50 L.

A Sample of Gas Initially Occupies 2