Calculate the number of moles in 95.0 g of O₂, and the volume that it would occupy at 80.0 $\degree$C and 3.50 atm.

Question

Quizplus · Accepted Answer

To calculate the number of moles in 95.0 g of O₂, we need to know its molar mass. Using the periodic table, we find that the molar mass of O₂ is: 1 x 15.99 g/mol (O) + 1 x 32.07 g/mol (S) + 2 x 126.9 g/mol (U) + 2 x 10.81 g/mol (B) = 321.46 g/mol Next, we can use the formula: moles = mass (in grams) / molar mass moles = 95.0 g / 321.46 g/mol = 0.2957 mol or 2.97 mol (rounded to three significant figures) To calculate the volume that 2.97 mol of O₂ would occupy at 80.0°F1F1F1S1F1F1F10C and 3.50 atm, we can use the ideal gas law equation: PV = nRT where P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/K·mol), and T is the temperature in Kelvin (K). First, we need to convert the temperature to Kelvin: T = (80 + 459.67) × (5/9) = 299.82 K Then we can rearrange the formula to solve for V: V = nRT / P V = (2.97 mol) × (0.0821 L·atm/K·mol) × (299.82 K) / (3.50 atm) = 24.6 L Therefore, the answer is D) 2.97 mol, 24.6 L.

Calculate the Number of Moles in 95 °\degree° C and 350 Atm

Calculate the Number of Moles in 95 $\degree$ C and 350 Atm