Propane burns in air according to the equation: C₃H₈(g) + 5O₂(g) $\rightarrow$ 3CO₂(g) + 4H₂O(g) What volume of CO₂would be formed if 5.00 L of propane burns, assuming that all of the gases are under the same conditions?

Question

Quizplus · Accepted Answer

According to the balanced equation, 1 mole of C3H8 produces 3 moles of CO2. Therefore, 5.00 L of C3H8 will produce 3 times that volume of CO2, which is 15.0 L, assuming all gases are under the same conditions.

Propane Burns in Air According to the Equation: C3H8(g) →\rightarrow→ 3CO2(g) + 4H2O(g) What Volume of CO2 would Be Formed

Propane Burns in Air According to the Equation: C₃H₈(g) $\rightarrow$ 3CO₂(g) + 4H₂O(g) What Volume of CO₂would Be Formed