Propane burns in air according to the equation: C₃H₈(g) + 5O₂(g) $\rightarrow$ 3CO₂(g) + 4H₂O(g) What volume of O₂would be required if 5.00 L of propane burns, assuming that all of the gases are under the same conditions?

Question

Quizplus · Accepted Answer

According to the balanced equation, 1 mole of C₃H₈ requires 5 moles of O₂. Therefore, 5.00 L of C₃H₈ would require 5 times that volume of O₂, which is 25.0 L.

Propane Burns in Air According to the Equation: C3H8(g) →\rightarrow→ 3CO2(g) + 4H2O(g) What Volume of O2 would Be Required

Propane Burns in Air According to the Equation: C₃H₈(g) $\rightarrow$ 3CO₂(g) + 4H₂O(g) What Volume of O₂would Be Required