Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt): 2Na(s) + Cl₂(g) $\rightarrow$ 2NaCl(s) If 3.6 moles of chlorine react with sufficient sodium, how many grams of sodium chloride should form?

Question

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that 1 mole of chlorine reacts with 2 moles of sodium to yield 2 moles of sodium chloride. Therefore, 3.6 moles of chlorine will react with 7.2 moles of sodium to yield 7.2 moles of sodium chloride.

The molar mass of NaCl is 58.44 g/mol, so 7.2 moles of NaCl will have a mass of:
7.2 mol x 58.44 g/mol = 421.25 g = 4.2 x 10^2 g

Therefore, the correct answer is C, 4.2 x 10^2 g.

Consider the Reaction Between Sodium Metal and Chlorine Gas to Form