Consider the reaction between acetylene, C₂H₂, and oxygen in a welding torch: 2C₂H₂(g)+ 5O₂(g) $\rightarrow$ 4CO₂(g) + 2H₂O(g) If 5.4 moles of acetylene react with sufficient oxygen, how many grams of CO₂ should form?

Question

Quizplus · Accepted Answer

According to the balanced chemical equation, 2 moles of acetylene produce 4 moles of CO₂. Therefore, 5.4 moles of acetylene will produce 10.8 moles of CO₂. Using the molar mass of CO₂ (60.07 g/mol), we can calculate the mass of CO₂ formed: mass = moles x molar mass mass = 10.8 mol x 60.07 g/mol mass = 647.5 g Rounding to the appropriate number of significant figures gives us: mass = 4.8 x 10² g

Consider the Reaction Between Acetylene, C2H2, and Oxygen in a Welding

Consider the Reaction Between Acetylene, C₂H₂, and Oxygen in a Welding