Aluminum reacts with oxygen according to the following reaction: 4Al(s) + 3O₂(g)$\rightarrow$2Al₂O₃(s) If 24 moles of aluminum are combined with 12 moles of oxygen, how many moles of Al₂O₃should form?

Question

Quizplus · Accepted Answer

The balanced equation shows that 4 moles of Al react with 3 moles of O2 to produce 2 moles of Al2O3. With 24 moles of Al and 12 moles of O2, Al is the limiting reactant. 24 moles of Al will produce (24/4)*2 = 12 moles of Al2O3. However, since O2 is also limited to 12 moles, it can only produce (12/3)*2 = 8 moles of Al2O3. Thus, 8 moles of Al2O3 will form.

Aluminum Reacts with Oxygen According to the Following Reaction: 4Al(s) →\rightarrow→

Aluminum Reacts with Oxygen According to the Following Reaction: 4Al(s) $\rightarrow$