Solve. Check for extraneous solutions.
-$$x ^ { 1 / 3 } - 2 = 4$$
A) $\{ 64 \}$
B) $\{ 36 \}$
C) $\{ \sqrt [ 3 ] { 6 } \}$
D) $\{ 216 \}$

Question

Quizplus · Accepted Answer

To solve $x^{1/3} - 2 = 4$, add 2 to both sides to get $x^{1/3} = 6$. Cube both sides to find $x = 6^3 = 216$. Check for extraneous solutions by substituting back into the original equation: $216^{1/3} - 2 = 6 - 2 = 4$, which is correct.

Solve Check for Extraneous Solutions x1/3−2=4x ^ { 1 / 3 } - 2 = 4x1/3−2=4

Solve Check for Extraneous Solutions $x ^ { 1 / 3 } - 2 = 4$