Solve the problem.
-The length a spring is stretched from its natural length with work, W foot-pounds, is given by $$L = \sqrt { \frac { 2 W } { k } }$$
A) 28.1 foot-pounds
B) 41.7 foot-pounds
C) 91.7 foot-pounds
D) 183.4 foot-pounds

Question

Quizplus · Accepted Answer

Given the formula for the length a spring is stretched from its natural length by work $W$ foot-pounds, $L = \sqrt { \frac { 2 W } { k } }$, and assuming $L = 6$ feet and $k = 8$ pounds per foot, we can solve for $W$. Rearranging the formula to solve for $W$, we get $W = \frac{kL^2}{2}$. Substituting $L = 6$ and $k = 8$, we find $W = \frac{8 \times 6^2}{2} = \frac{8 \times 36}{2} = 4 \times 36 = 144$ foot-pounds. However, none of the provided options match this calculation directly, indicating a potential misunderstanding in the question's setup or a mistake in the calculation based on the given options. Given the correct approach to solving for $W$, the answer should be recalculated or the question revisited for clarity.

Solve the Problem L=2WkL = \sqrt { \frac { 2 W } { k } }L=k2W​​

Solve the Problem $L = \sqrt { \frac { 2 W } { k } }$