Divide.
-$$\frac { x ^ { 2 } - 1 } { x } \div \frac { x - 1 } { x - 3 }$$

Question

Quizplus · Accepted Answer

To divide two fractions, we flip the second fraction and change the operation to multiplication. So the given expression becomes:
$$\frac { x^2-1 }{ x }\times \frac { x-3 }{ x-1 } $$
Now we can factor the numerator:
$$\frac { ( x+1 ) ( x-1 ) }{ x }\times \frac { x-3 }{ x-1 } $$
We can cancel out the common factor of $x-1$ in the numerator and denominator:
$$\frac { ( x+1 ) \cancel{( x-1 )} }{ x }\times \frac { x-3 }{ \cancel{x-1} } $$
And finally, we can factor the numerator to get the answer:
$$\frac { ( x+1 ) ( x-3 ) }{ x }$$

Divide - x2−1x÷x−1x−3\frac { x ^ { 2 } - 1 } { x } \div \frac { x - 1 } { x - 3 }xx2−1​÷x−3x−1​

Divide
- $\frac { x ^ { 2 } - 1 } { x } \div \frac { x - 1 } { x - 3 }$