Add.
-$$\frac { x ^ { 2 } - 8 x } { x - 7 } + \frac { 8 x - x ^ { 2 } } { x - 7 }$$
A) $\frac { 16 x } { x - 7 }$
B) $\frac { 1 } { x - 7 }$
C) 1
D) 0

Name: Add. -\[\frac { x ^ { 2 } - 8 x } { x - 7 } + \frac { 8 x - x ^ { 2 } } { x - 7 }\] A) $\frac { 16 x } { x - 7 }$ B) $\frac { 1 } { x - 7 }$ C) 1 D) 0
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Question

Quizplus · Accepted Answer

The expressions have the same denominator, so we can add the numerators: $(x^2 - 8x) + (8x - x^2) = 0$. Thus, the result is $\frac{0}{x-7} = 0$.

Add - x2−8xx−7+8x−x2x−7\frac { x ^ { 2 } - 8 x } { x - 7 } + \frac { 8 x - x ^ { 2 } } { x - 7 }x−7x2−8x​+x−78x−x2​

Add
- $\frac { x ^ { 2 } - 8 x } { x - 7 } + \frac { 8 x - x ^ { 2 } } { x - 7 }$