Add.
-$$\frac { x ^ { 2 } - 5 x } { x ^ { 2 } + 6 x + 9 } + \frac { 4 x - 12 } { x ^ { 2 } + 6 x + 9 }$$
A) $\frac { x + 4 } { x + 3 }$

B) $\frac { x - 4 } { x + 3 }$

C) $\frac { ( x - 4 ) ( x - 3 ) } { ( x + 3 ) ^ { 2 } }$

D) $\frac { 1 } { x + 3 }$

Question

Add.
-$$\frac { x ^ { 2 } - 5 x } { x ^ { 2 } + 6 x + 9 } + \frac { 4 x - 12 } { x ^ { 2 } + 6 x + 9 }$$
A) $\frac { x + 4 } { x + 3 }$

B) $\frac { x - 4 } { x + 3 }$

C) $\frac { ( x - 4 ) ( x - 3 ) } { ( x + 3 ) ^ { 2 } }$

D) $\frac { 1 } { x + 3 }$

Quizplus · Accepted Answer

The denominators are the same, so we can combine the numerators: $\frac{x^2 - 5x + 4x - 12}{x^2 + 6x + 9} = \frac{x^2 - x - 12}{(x + 3)^2}$. Factoring the numerator gives $\frac{(x - 4)(x + 3)}{(x + 3)^2}$. Simplifying by canceling one (x + 3) term gives $\frac{x - 4}{x + 3}$.

Add - x2−5xx2+6x+9+4x−12x2+6x+9\frac { x ^ { 2 } - 5 x } { x ^ { 2 } + 6 x + 9 } + \frac { 4 x - 12 } { x ^ { 2 } + 6 x + 9 }x2+6x+9x2−5x​+x2+6x+94x−12​

Add
- $\frac { x ^ { 2 } - 5 x } { x ^ { 2 } + 6 x + 9 } + \frac { 4 x - 12 } { x ^ { 2 } + 6 x + 9 }$