Solve by factoring.
-$- 10 x ^ { 2 } + 10 x + 200 = 0$
A) $\{ - 5,4 \}$
B) $\{ - 5 , - 4 \}$
C) $\{ 5,4 \}$
D) $\{ 5 , - 4 \}$

Name: Solve by factoring. -$- 10 x ^ { 2 } + 10 x + 200 = 0$ A) $\{ - 5,4 \}$ B) $\{ - 5 , - 4 \}$ C) $\{ 5,4 \}$ D) $\{ 5 , - 4 \}$
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Question

Quizplus · Accepted Answer

First, factor out the common factor of 10: $10(-x^2 + x + 20) = 0$. Then, factor the quadratic equation to get $(-x + 5)(x + 4) = 0$, which gives the solutions $x = 5$ and $x = -4$.

Solve by Factoring −10x2+10x+200=0- 10 x ^ { 2 } + 10 x + 200 = 0−10x2+10x+200=0

Solve by Factoring $- 10 x ^ { 2 } + 10 x + 200 = 0$