Find the vertex of the parabola associated with the quadratic equation.
-$y = x ^ { 2 } + 2 x + 1$
A) $( 1,1 )$
B) $( - 1,0 )$
C) $( - 1,1 )$
D) $( 1,0$

Question

Quizplus · Accepted Answer

The vertex of a parabola given by the equation $y = ax^2 + bx + c$ can be found using the formula $(-b/2a, f(-b/2a))$. For the given equation $y = x^2 + 2x + 1$, $a = 1$ and $b = 2$, so the x-coordinate of the vertex is $-b/2a = -2/(2*1) = -1$. Plugging this back into the equation gives $y = (-1)^2 + 2(-1) + 1 = 0$. Therefore, the vertex is $(-1, 0)$.

Find the Vertex of the Parabola Associated with the Quadratic y=x2+2x+1y = x ^ { 2 } + 2 x + 1y=x2+2x+1

Find the Vertex of the Parabola Associated with the Quadratic $y = x ^ { 2 } + 2 x + 1$