The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu$ $$\begin{array}{l}
\text { Test of mu } = 55 \mathrm { vs } . \text { not } = 55\\
\begin{array} { l c c c c r r }
\mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { T } & \text { P } \
58 & 51.24 & 6.112029 & 0.802549 & ( 49.63293,52.84707 ) & - 4.685074 & 0.000018 \
\hline
\end{array}
\end{array}$$ How many degrees of freedom are there?
A) 59
B) 58
C) 55
D) 57

Question

The following output from MINITAB presents the results of a hypothesis test for a population mean $\mu$ $$\begin{array}{l}
\text { Test of mu } = 55 \mathrm { vs } . \text { not } = 55\\
\begin{array} { l c c c c r r } 
\mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } & 95 \% \text { CI } & \text { T } & \text { P } \
58 & 51.24 & 6.112029 & 0.802549 & ( 49.63293,52.84707 ) & - 4.685074 & 0.000018 \
\hline
\end{array}
\end{array}$$ How many degrees of freedom are there?
A) 59
B) 58
C) 55
D) 57

Quizplus · Accepted Answer

The degrees of freedom for a one-sample t-test is calculated as $n - 1$, where $n$ is the sample size. Here, $n = 58$, so the degrees of freedom is $58 - 1 = 57$.

The Following Output from MINITAB Presents the Results of a Hypothesis