The weights of 6-week-old poults (juvenile turkeys) are normally distributed with a mean 9.0 pounds and standard deviation 2.4 pounds. A turkey farmer wants to provide a money-back Guarantee that her 6-week poults will weigh at least a certain amount. What weight should she Guarantee so that she will have to give her customer's money back only 1% of the time?
A) 3.41 lb
B) 3.07 lb
C) 2.73 lb
D) 4.09 lb

Question

Quizplus · Accepted Answer

To find the weight that corresponds to the top 99% of the distribution, we need to find the z-score that corresponds to the 1st percentile (since 1% of the time the weight will be less than this value). The z-score for the 1st percentile is approximately -2.33. Using the formula: weight = mean + (z-score * standard deviation), we get: weight = 9.0 + (-2.33 * 2.4) = 3.41 lb.

The Weights of 6-Week-Old Poults (Juvenile Turkeys) Are Normally Distributed