Analyze the following code. public class Test {
Public static void main(String[] args) {
System.out.println(max(1, 2));
}
Public static double max(int num1, double num2) {
System.out.println("max(int, double) is invoked");
If (num1 num2)
Return num1;
Else
Return num2;
}
Public static double max(double num1, int num2) {
System.out.println("max(double, int) is invoked");
If (num1 num2)
Return num1;
Else
Return num2;
}
}
A) The program runs and prints 2 followed by "max(double, int)" is invoked.
B) The program cannot compile because the compiler cannot determine which max method should be invoked.
C) The program runs and prints "max(int, double) is invoked" followed by 2.
D) The program runs and prints 2 followed by "max(int, double)" is invoked.
E) The program cannot compile because you cannot have the print statement in a non-void method.

Question

Analyze the following code. public class Test {
Public static void main(String[] args) {
System.out.println(max(1, 2));
}
Public static double max(int num1, double num2) {
System.out.println("max(int, double) is invoked");
If (num1 > num2)
Return num1;
Else
Return num2;
}
Public static double max(double num1, int num2) {
System.out.println("max(double, int) is invoked");
If (num1 > num2)
Return num1;
Else
Return num2;
}
}
A) The program runs and prints 2 followed by "max(double, int)" is invoked.
B) The program cannot compile because the compiler cannot determine which max method should be invoked.
C) The program runs and prints "max(int, double) is invoked" followed by 2.
D) The program runs and prints 2 followed by "max(int, double)" is invoked.
E) The program cannot compile because you cannot have the print statement in a non-void method.

Quizplus · Accepted Answer

CThe program can compile and run because Java supports method overloading, which allows methods to have the same name but different parameter types. The print statement inside a non-void method is also allowed as long as the method returns a value of the correct type. The compiler can determine which method to invoke based on the argument types passed to the method. In this case, the arguments are an int and a double, so the "max(int, double)" version is invoked, printing "max(int, double) is invoked" followed by the value 2.

Analyze the Following Code. Public Class Test