Analyze the following code: public class Test {
Public static void main(String[] args) {
System.out.println(xMethod(5, 500L));
}
Public static int xMethod(int n, long l) {
System.out.println("int, long");
Return n;
}
Public static long xMethod(long n, long l) {
System.out.println("long, long");
Return n;
}
}
A) The program does not compile because the compiler cannot distinguish which xmethod to invoke.
B) The program runs fine but displays things other than 5.
C) The program displays long, long followed by 5.
D) The program displays int, long followed by 5.

Question

Quizplus · Accepted Answer

The program will compile and run fine. When the xMethod is called with arguments 5 and 500L, the compiler has to choose which version of the method to use. Since the first argument is an int, and the second argument is a long, the compiler will choose the xMethod that takes an int as its first argument and a long as its second argument. This method will print "int, long" and return the value of n, which is 5. Therefore, the program will display "int, long" followed by 5.

Analyze the Following Code: Public Class Test