Find the value of the test statistic z using z $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$
-The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statistics include n = 696 drowning deaths of children with 30% of them attributable to beaches.
A) 3.05
B) 2.88
C) -2.88
D) -3.05

Question

Quizplus · Accepted Answer

First, we need to calculate the estimated proportion of drowning deaths of children attributable to beaches:
$\hat{p} = \frac{696 	imes 0.30}{696} = 0.30$
Then we can plug in the values:
$z = \frac{0.30 - 0.25}{\sqrt{\frac{0.25 	imes 0.75}{696}}} = 3.051$
Rounding to two decimal places, the answer is A: 3.05.

Find the Value of the Test Statistic Z Using Z z=p^−ppqnz = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }z=npq​​p^​−p​

Find the Value of the Test Statistic Z Using Z $z = \frac { \hat { p } - p } { \sqrt { \frac { p q } { n } } }$