Express the confidence interval $( 0.432,0.52 )$ in the form of $\hat { p } \pm \mathrm { E }$.
A) $0.432 \pm 0.088$
B) $0.476 \pm 0.088$
C) $0.432 \pm 0.044$
D) $0.476 \pm 0.044$

Question

Quizplus · Accepted Answer

The midpoint of the interval $(0.432, 0.52)$ is $\hat{p} = \frac{0.432 + 0.52}{2} = 0.476$. The margin of error $E$ is half the width of the interval: $E = \frac{0.52 - 0.432}{2} = 0.044$. Thus, the confidence interval can be expressed as $0.476 \pm 0.044$.

Express the Confidence Interval (0.432,0.52)( 0.432,0.52 )(0.432,0.52) In the Form Of p^±E\hat { p } \pm \mathrm { E }p^​±E

Express the Confidence Interval $( 0.432,0.52 )$ In the Form Of $\hat { p } \pm \mathrm { E }$