Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the
given statistics and confidence level. Round the margin of error to four decimal places.
-In a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the 95% confidence interval used to estimate the population proportion.
A) 0.0664
B) 0.0598
C) 0.00225
D) 0.116

Question

Quizplus · Accepted Answer

The margin of error for a 95% confidence interval is given by:E = z * sqrt((p(1-p))/n)where z is the z-score corresponding to the desired confidence level, p is the sample proportion, and n is the sample size.In this case, we have:z = 1.96 (for a 95% confidence level)p = 129/192 = 0.672n = 192Plugging these values into the formula, we get:E = 1.96 * sqrt((0.672(1-0.672))/192) = 0.0664Therefore, the margin of error for the 95% confidence interval is 0.0664.

Assume That a Sample Is Used to Estimate a Population